Integrand size = 27, antiderivative size = 173 \[ \int \frac {\cos ^4(c+d x) \sin (c+d x)}{(a+b \sin (c+d x))^3} \, dx=\frac {3 \left (4 a^2-b^2\right ) x}{2 b^5}-\frac {3 a \left (4 a^2-3 b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{b^5 \sqrt {a^2-b^2} d}+\frac {\cos ^3(c+d x) (2 a+b \sin (c+d x))}{2 b^2 d (a+b \sin (c+d x))^2}+\frac {3 \cos (c+d x) \left (4 a^2-b^2+2 a b \sin (c+d x)\right )}{2 b^4 d (a+b \sin (c+d x))} \]
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Time = 0.21 (sec) , antiderivative size = 173, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.185, Rules used = {2942, 2814, 2739, 632, 210} \[ \int \frac {\cos ^4(c+d x) \sin (c+d x)}{(a+b \sin (c+d x))^3} \, dx=-\frac {3 a \left (4 a^2-3 b^2\right ) \arctan \left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{b^5 d \sqrt {a^2-b^2}}+\frac {3 x \left (4 a^2-b^2\right )}{2 b^5}+\frac {3 \cos (c+d x) \left (4 a^2+2 a b \sin (c+d x)-b^2\right )}{2 b^4 d (a+b \sin (c+d x))}+\frac {\cos ^3(c+d x) (2 a+b \sin (c+d x))}{2 b^2 d (a+b \sin (c+d x))^2} \]
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Rule 210
Rule 632
Rule 2739
Rule 2814
Rule 2942
Rubi steps \begin{align*} \text {integral}& = \frac {\cos ^3(c+d x) (2 a+b \sin (c+d x))}{2 b^2 d (a+b \sin (c+d x))^2}-\frac {3 \int \frac {\cos ^2(c+d x) (-2 b-4 a \sin (c+d x))}{(a+b \sin (c+d x))^2} \, dx}{4 b^2} \\ & = \frac {\cos ^3(c+d x) (2 a+b \sin (c+d x))}{2 b^2 d (a+b \sin (c+d x))^2}+\frac {3 \cos (c+d x) \left (4 a^2-b^2+2 a b \sin (c+d x)\right )}{2 b^4 d (a+b \sin (c+d x))}+\frac {3 \int \frac {4 a b+2 \left (4 a^2-b^2\right ) \sin (c+d x)}{a+b \sin (c+d x)} \, dx}{4 b^4} \\ & = \frac {3 \left (4 a^2-b^2\right ) x}{2 b^5}+\frac {\cos ^3(c+d x) (2 a+b \sin (c+d x))}{2 b^2 d (a+b \sin (c+d x))^2}+\frac {3 \cos (c+d x) \left (4 a^2-b^2+2 a b \sin (c+d x)\right )}{2 b^4 d (a+b \sin (c+d x))}-\frac {\left (3 \left (-4 a b^2+2 a \left (4 a^2-b^2\right )\right )\right ) \int \frac {1}{a+b \sin (c+d x)} \, dx}{4 b^5} \\ & = \frac {3 \left (4 a^2-b^2\right ) x}{2 b^5}+\frac {\cos ^3(c+d x) (2 a+b \sin (c+d x))}{2 b^2 d (a+b \sin (c+d x))^2}+\frac {3 \cos (c+d x) \left (4 a^2-b^2+2 a b \sin (c+d x)\right )}{2 b^4 d (a+b \sin (c+d x))}-\frac {\left (3 a \left (4 a^2-3 b^2\right )\right ) \text {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{b^5 d} \\ & = \frac {3 \left (4 a^2-b^2\right ) x}{2 b^5}+\frac {\cos ^3(c+d x) (2 a+b \sin (c+d x))}{2 b^2 d (a+b \sin (c+d x))^2}+\frac {3 \cos (c+d x) \left (4 a^2-b^2+2 a b \sin (c+d x)\right )}{2 b^4 d (a+b \sin (c+d x))}+\frac {\left (6 a \left (4 a^2-3 b^2\right )\right ) \text {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )}{b^5 d} \\ & = \frac {3 \left (4 a^2-b^2\right ) x}{2 b^5}-\frac {3 a \left (4 a^2-3 b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{b^5 \sqrt {a^2-b^2} d}+\frac {\cos ^3(c+d x) (2 a+b \sin (c+d x))}{2 b^2 d (a+b \sin (c+d x))^2}+\frac {3 \cos (c+d x) \left (4 a^2-b^2+2 a b \sin (c+d x)\right )}{2 b^4 d (a+b \sin (c+d x))} \\ \end{align*}
Time = 2.42 (sec) , antiderivative size = 274, normalized size of antiderivative = 1.58 \[ \int \frac {\cos ^4(c+d x) \sin (c+d x)}{(a+b \sin (c+d x))^3} \, dx=\frac {-\frac {48 a \left (4 a^2-3 b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{\sqrt {a^2-b^2}}+\frac {96 a^4 c+24 a^2 b^2 c-12 b^4 c+96 a^4 d x+24 a^2 b^2 d x-12 b^4 d x+96 a^3 b \cos (c+d x)+12 b^2 \left (-4 a^2+b^2\right ) (c+d x) \cos (2 (c+d x))-8 a b^3 \cos (3 (c+d x))+192 a^3 b c \sin (c+d x)-48 a b^3 c \sin (c+d x)+192 a^3 b d x \sin (c+d x)-48 a b^3 d x \sin (c+d x)+72 a^2 b^2 \sin (2 (c+d x))-10 b^4 \sin (2 (c+d x))+b^4 \sin (4 (c+d x))}{(a+b \sin (c+d x))^2}}{16 b^5 d} \]
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Time = 1.72 (sec) , antiderivative size = 288, normalized size of antiderivative = 1.66
method | result | size |
derivativedivides | \(\frac {-\frac {4 \left (\frac {-\frac {5 a^{2} b^{2} \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4}-\frac {b \left (6 a^{4}+11 a^{2} b^{2}-2 b^{4}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4 a}-\frac {b^{2} \left (19 a^{2}-4 b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{4}-\frac {a b \left (6 a^{2}-b^{2}\right )}{4}}{{\left (\left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a +2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a \right )}^{2}}+\frac {3 a \left (4 a^{2}-3 b^{2}\right ) \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{4 \sqrt {a^{2}-b^{2}}}\right )}{b^{5}}+\frac {\frac {4 \left (\frac {\left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{2}}{4}+\frac {3 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a b}{2}-\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) b^{2}}{4}+\frac {3 a b}{2}\right )}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{2}}+3 \left (4 a^{2}-b^{2}\right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{b^{5}}}{d}\) | \(288\) |
default | \(\frac {-\frac {4 \left (\frac {-\frac {5 a^{2} b^{2} \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4}-\frac {b \left (6 a^{4}+11 a^{2} b^{2}-2 b^{4}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4 a}-\frac {b^{2} \left (19 a^{2}-4 b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{4}-\frac {a b \left (6 a^{2}-b^{2}\right )}{4}}{{\left (\left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a +2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a \right )}^{2}}+\frac {3 a \left (4 a^{2}-3 b^{2}\right ) \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{4 \sqrt {a^{2}-b^{2}}}\right )}{b^{5}}+\frac {\frac {4 \left (\frac {\left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{2}}{4}+\frac {3 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a b}{2}-\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) b^{2}}{4}+\frac {3 a b}{2}\right )}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{2}}+3 \left (4 a^{2}-b^{2}\right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{b^{5}}}{d}\) | \(288\) |
risch | \(\frac {6 x \,a^{2}}{b^{5}}-\frac {3 x}{2 b^{3}}+\frac {i {\mathrm e}^{2 i \left (d x +c \right )}}{8 b^{3} d}+\frac {3 a \,{\mathrm e}^{i \left (d x +c \right )}}{2 b^{4} d}+\frac {3 a \,{\mathrm e}^{-i \left (d x +c \right )}}{2 b^{4} d}-\frac {i {\mathrm e}^{-2 i \left (d x +c \right )}}{8 b^{3} d}-\frac {i \left (-8 i a^{3} b \,{\mathrm e}^{3 i \left (d x +c \right )}+3 i a \,b^{3} {\mathrm e}^{3 i \left (d x +c \right )}+20 i a^{3} b \,{\mathrm e}^{i \left (d x +c \right )}-5 i a \,b^{3} {\mathrm e}^{i \left (d x +c \right )}+14 a^{4} {\mathrm e}^{2 i \left (d x +c \right )}+3 b^{2} a^{2} {\mathrm e}^{2 i \left (d x +c \right )}-2 b^{4} {\mathrm e}^{2 i \left (d x +c \right )}-7 a^{2} b^{2}+2 b^{4}\right )}{\left (-i b \,{\mathrm e}^{2 i \left (d x +c \right )}+i b +2 a \,{\mathrm e}^{i \left (d x +c \right )}\right )^{2} d \,b^{5}}-\frac {6 i a^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}\, a +a^{2}-b^{2}\right )}{b \sqrt {a^{2}-b^{2}}}\right )}{\sqrt {a^{2}-b^{2}}\, d \,b^{5}}+\frac {9 i a \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}\, a +a^{2}-b^{2}\right )}{b \sqrt {a^{2}-b^{2}}}\right )}{2 \sqrt {a^{2}-b^{2}}\, d \,b^{3}}+\frac {6 i a^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}\, a -a^{2}+b^{2}\right )}{b \sqrt {a^{2}-b^{2}}}\right )}{\sqrt {a^{2}-b^{2}}\, d \,b^{5}}-\frac {9 i a \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}\, a -a^{2}+b^{2}\right )}{b \sqrt {a^{2}-b^{2}}}\right )}{2 \sqrt {a^{2}-b^{2}}\, d \,b^{3}}\) | \(541\) |
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Leaf count of result is larger than twice the leaf count of optimal. 377 vs. \(2 (162) = 324\).
Time = 0.35 (sec) , antiderivative size = 837, normalized size of antiderivative = 4.84 \[ \int \frac {\cos ^4(c+d x) \sin (c+d x)}{(a+b \sin (c+d x))^3} \, dx=\left [\frac {6 \, {\left (4 \, a^{4} b^{2} - 5 \, a^{2} b^{4} + b^{6}\right )} d x \cos \left (d x + c\right )^{2} + 8 \, {\left (a^{3} b^{3} - a b^{5}\right )} \cos \left (d x + c\right )^{3} - 6 \, {\left (4 \, a^{6} - a^{4} b^{2} - 4 \, a^{2} b^{4} + b^{6}\right )} d x - 3 \, {\left (4 \, a^{5} + a^{3} b^{2} - 3 \, a b^{4} - {\left (4 \, a^{3} b^{2} - 3 \, a b^{4}\right )} \cos \left (d x + c\right )^{2} + 2 \, {\left (4 \, a^{4} b - 3 \, a^{2} b^{3}\right )} \sin \left (d x + c\right )\right )} \sqrt {-a^{2} + b^{2}} \log \left (\frac {{\left (2 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2} + 2 \, {\left (a \cos \left (d x + c\right ) \sin \left (d x + c\right ) + b \cos \left (d x + c\right )\right )} \sqrt {-a^{2} + b^{2}}}{b^{2} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2}}\right ) - 6 \, {\left (4 \, a^{5} b - 3 \, a^{3} b^{3} - a b^{5}\right )} \cos \left (d x + c\right ) - 2 \, {\left ({\left (a^{2} b^{4} - b^{6}\right )} \cos \left (d x + c\right )^{3} + 6 \, {\left (4 \, a^{5} b - 5 \, a^{3} b^{3} + a b^{5}\right )} d x + 3 \, {\left (6 \, a^{4} b^{2} - 7 \, a^{2} b^{4} + b^{6}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{4 \, {\left ({\left (a^{2} b^{7} - b^{9}\right )} d \cos \left (d x + c\right )^{2} - 2 \, {\left (a^{3} b^{6} - a b^{8}\right )} d \sin \left (d x + c\right ) - {\left (a^{4} b^{5} - b^{9}\right )} d\right )}}, \frac {3 \, {\left (4 \, a^{4} b^{2} - 5 \, a^{2} b^{4} + b^{6}\right )} d x \cos \left (d x + c\right )^{2} + 4 \, {\left (a^{3} b^{3} - a b^{5}\right )} \cos \left (d x + c\right )^{3} - 3 \, {\left (4 \, a^{6} - a^{4} b^{2} - 4 \, a^{2} b^{4} + b^{6}\right )} d x - 3 \, {\left (4 \, a^{5} + a^{3} b^{2} - 3 \, a b^{4} - {\left (4 \, a^{3} b^{2} - 3 \, a b^{4}\right )} \cos \left (d x + c\right )^{2} + 2 \, {\left (4 \, a^{4} b - 3 \, a^{2} b^{3}\right )} \sin \left (d x + c\right )\right )} \sqrt {a^{2} - b^{2}} \arctan \left (-\frac {a \sin \left (d x + c\right ) + b}{\sqrt {a^{2} - b^{2}} \cos \left (d x + c\right )}\right ) - 3 \, {\left (4 \, a^{5} b - 3 \, a^{3} b^{3} - a b^{5}\right )} \cos \left (d x + c\right ) - {\left ({\left (a^{2} b^{4} - b^{6}\right )} \cos \left (d x + c\right )^{3} + 6 \, {\left (4 \, a^{5} b - 5 \, a^{3} b^{3} + a b^{5}\right )} d x + 3 \, {\left (6 \, a^{4} b^{2} - 7 \, a^{2} b^{4} + b^{6}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{2 \, {\left ({\left (a^{2} b^{7} - b^{9}\right )} d \cos \left (d x + c\right )^{2} - 2 \, {\left (a^{3} b^{6} - a b^{8}\right )} d \sin \left (d x + c\right ) - {\left (a^{4} b^{5} - b^{9}\right )} d\right )}}\right ] \]
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Timed out. \[ \int \frac {\cos ^4(c+d x) \sin (c+d x)}{(a+b \sin (c+d x))^3} \, dx=\text {Timed out} \]
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Exception generated. \[ \int \frac {\cos ^4(c+d x) \sin (c+d x)}{(a+b \sin (c+d x))^3} \, dx=\text {Exception raised: ValueError} \]
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Leaf count of result is larger than twice the leaf count of optimal. 429 vs. \(2 (162) = 324\).
Time = 0.37 (sec) , antiderivative size = 429, normalized size of antiderivative = 2.48 \[ \int \frac {\cos ^4(c+d x) \sin (c+d x)}{(a+b \sin (c+d x))^3} \, dx=\frac {\frac {3 \, {\left (4 \, a^{2} - b^{2}\right )} {\left (d x + c\right )}}{b^{5}} - \frac {6 \, {\left (4 \, a^{3} - 3 \, a b^{2}\right )} {\left (\pi \left \lfloor \frac {d x + c}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (a\right ) + \arctan \left (\frac {a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + b}{\sqrt {a^{2} - b^{2}}}\right )\right )}}{\sqrt {a^{2} - b^{2}} b^{5}} + \frac {2 \, {\left (6 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 12 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} + 15 \, a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} - 2 \, b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} + 54 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 36 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 45 \, a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 4 \, b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 90 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 12 \, a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 36 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 29 \, a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 2 \, b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 42 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 4 \, a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 12 \, a^{4} - a^{2} b^{2}\right )}}{{\left (a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 2 \, b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 2 \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 2 \, b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + a\right )}^{2} a b^{4}}}{2 \, d} \]
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Time = 14.67 (sec) , antiderivative size = 1743, normalized size of antiderivative = 10.08 \[ \int \frac {\cos ^4(c+d x) \sin (c+d x)}{(a+b \sin (c+d x))^3} \, dx=\text {Too large to display} \]
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